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35d3fab960
The previous implementation could emit 'wildcard' channel layouts in too many scenarios. A wildcard channel count is -1 or -2, and indicates that any number of channels is supported on the bus. If the input and output layouts must match, then a layout of [-1, -1] should be returned. If any layout is valid in both directions, then a layout of [-1, -2] should be returned. In the case where we have a bus A and opposite bus B, we will now only emit a wildcard count for bus A if every bus standard bus layout up to a channel count of 16 can be applied successfully without changing the bus count of B. |
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| Builds/VisualStudio2022 | ||
| JuceLibraryCode | ||
| WindowsDLL.jucer | ||